claimroutine
Local square-root obstruction for characters
Character has a square root exactly when locally
local test for the square-root obstruction
Claim·§4.6 The endomorphism dichotomy and descent up to isogeny·inside lemSign-splitting cochain with square-root character
Statement (paper)
Let be a place of and let be a finite character of with values in and trivial coefficient action. Then its square-root obstruction vanishes if and only if has a continuous character square root, which holds if and only if, via local reciprocity, is trivial on the order-two subgroup of , that is, . At the real place the same assertion holds, since . Moreover, at a prime outside the local class of is zero.
In plain English
For a finite character of (trivial action), the obstruction to a continuous character square root vanishes exactly when under local reciprocity; the same holds at the real place, and at primes outside the local class of is zero.
Why it's here
This turns the existence of a square root of a character into a concrete local test, , so a global character can be chosen with matching the class place by place. The vanishing of locally outside means no condition is imposed there, which keeps unramified outside in the later steps of the proof of the sign-splitting lemma.
Classified routine:
A standard local computation: under local reciprocity, the image of squaring on characters of is exactly the characters trivial on its 2-torsion . The connecting map comes from the Kummer-type squaring sequence. Vanishing of outside is bookkeeping from how was built.
Uses
Nothing else in the paper
Used by
Sources
PaperOpen
- Section
- §4.6 The endomorphism dichotomy and descent up to isogeny
- Page
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sections/04-height.tex:782
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