claimroutineinferred_dep
Twist scaling reduces to one parameter
Reduces to one with class- points on and
collapses two twist parameters to one
Statement (paper)
Write with . For every , the map is an isomorphism that preserves -coordinate square classes. Hence, taking in the formula, it suffices to find one for which both and have a rational point with nonzero -coordinate of class , the class of .
In plain English
Writing with , the map is an isomorphism that preserves -coordinate square classes for every . So it suffices to find one such that both and have a rational point with nonzero -coordinate of class , the class of , taking in the formula.
Why it's here
The scaling by identifies the twist by with the twist by without changing square classes of -coordinates. The two-parameter requirement, one condition for and one for , therefore collapses to a single parameter with conditions on and . This simplifies the construction of integer witnesses in the proof of the pole-parity proposition, where and are as constrained by the cross-square conditions on the prime sets and .}</br>Wait, I must output valid JSON only.{
Classified routine:
Direct computation: quadratic twists by classes differing by a square are isomorphic via the standard change of variables , and since is a square this preserves square classes of -coordinates, giving a bookkeeping reduction inside the proof.
Uses
Used by
Nothing in the paper
Sources
PaperOpen
- Section
- §3.2 Preparing integer witnesses
- Page
- —
- Label
—- Line
sections/03-parity.tex:219
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- infoinferred_depoutline: "Twist scaling reduces to one parameter n" rests on par:cross-squares