claimroutineinferred_dep
Recurrence solves to O(e^τ) per volume
Recurrence gives per volume
solves the swap cost recurrence
Claim·§4.2 Transferring a finite circuit to address permutations·inside propPower-width chunk interchange in O(Ve^τ)
Statement (paper)
Let be a uniform upper bound for time divided by logical volume for the interchange of two chunks of radix- digits each, so that and . Since , it follows that , with the implied constant independent of and of all field lengths.
In plain English
If is the worst-case ratio of time to logical volume for interchanging two chunks of radix- digits, then and . Because , this gives with a constant independent of and the field lengths.
Why it's here
The three-shear swap reduces one interchange at level to circuit-driven shears whose recursive calls, after dividing by volume, contribute a factor times the level- cost plus linear overhead. Since , the geometric recurrence grows at most like , which yields the time bound claimed in the proposition once the fixed-tape schedule cost per node is accounted for.
Classified routine:
Unrolling the linear recurrence with ratio gives a geometric sum bounded by . This is a standard recurrence calculation that uses the shear decomposition from the previous claim.
Uses
Used by
Sources
PaperOpen
- Section
- §4.2 Transferring a finite circuit to address permutations
- Page
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- Label
—- Line
sections/04-swap.tex:197
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- infoinferred_depoutline: "Volume-normalized recurrence gives O(e^τ)" rests on claim-prop-power-interchange-3