claimroutineinferred_dep
Exact normalization identity via retained order
Pointwise product commutes with layout, giving exactly
exact identity the error analysis compares against
Claim·§7.1 The normalized convolution interface·inside propSynthetic convolution: error, cost, and format
Statement (paper)
Let denote the exact pointwise product and . Then , so applied to the pointwise product of the exact stored forward outputs of and equals , and its exact scaling by equals , since and give .
In plain English
The pointwise product commutes with the layout and normalization maps, . Hence applying to the pointwise product of the exact stored forward outputs of and gives , and scaling that by exactly gives .
Why it's here
This is the exact, rounding-free identity behind the convolution: the layout permutation and normalization can be left in place between the forward and opposite transforms, because the pointwise product passes through them. The convolution identity together with from the characters lemma then shows the result is . The later claims then only need to bound the rounding errors of the stored computation against this exact target and check the exact scaling by .
Classified routine:
Direct algebraic consequence of the convolution theorem for the synthetic DFT and the inverse relation from the characters lemma, plus the fact that pointwise products commute with coordinate permutations and diagonal scaling.
Uses
Used by
Sources
PaperOpen
- Section
- §7.1 The normalized convolution interface
- Page
- —
- Label
—- Line
sections/06-transforms.tex:657
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- infoinferred_depoutline: "Exact normalization identity via retained order" rests on lem:synthetic-transform-cost
- infoinferred_depoutline: "Exact normalization identity via retained order" rests on lem:synthetic-characters