claimroutine
Smooth part away from ball boundary is bounded
Bounds the smooth part away from the ball boundary on
handles the nonsingular part of the multiplier
Statement (paper)
The part of the multiplier away from the boundary of the ball is smooth, supported in , and vanishes to order two at zero. Decomposed into annuli , , and rescaled to the unit annulus after extracting , its pieces have uniformly bounded derivatives and kernels satisfying Lemma at with uniform constants. Hence, by the Littlewood--Paley estimate and , this part is bounded on by .
In plain English
The portion of the multiplier supported away from the boundary of the unit ball (supported in , vanishing to order two at zero) gives an operator bounded on with norm at most .
Why it's here
Splitting into annuli and rescaling to the unit annulus produces pieces whose kernels satisfy the dilate square function lemma at , where no logarithmic loss occurs. The order-two vanishing at zero supplies the factor , which is summable over , so the Littlewood–Paley estimate sums the pieces. This handles the non-singular part of the multiplier, leaving only the shells near the boundary for the -dependent argument.
Classified routine:
This is the standard treatment of the smooth, non-singular part of Stein's square function multiplier. It decomposes the multiplier into dyadic annuli and rescales, then applies the earlier dilate square function lemma at δ=1 together with Littlewood–Paley theory, summing the pieces via the geometric factor 2^{2ℓ}.
Uses
Used by
Sources
PaperOpen
- Section
- §11 Stein's square function
- Page
- —
- Label
—- Line
sections/stein_square.tex:223
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