claimroutineinferred_dep
Logarithmic residues force constant Y
Shows is constant on , so on
puts the curve in the fiber
Statement (paper)
On the persistent component , the function is constant. In particular on , and hence on by density. When some positive coordinate direction is nontangent to , one has on for the largest such index , and this forces (and ) to be constant on .
In plain English
On the persistent component the function is constant, so on and hence on by density. If some positive coordinate direction is nontangent to , then on for the largest such index , which forces and to be constant on .
Why it's here
This shows that the persistent component lies inside the affine fiber , which lets the next claim work with a fiber polynomial there. The idea is to use the normal-basis weight bound from the persistent-component claim together with the separated-weights choice. These rule out every index pattern except the one where the largest nontangent direction gives , and that relation forces to be constant.
Classified routine:
The index-pattern reduction follows from the earlier persistent-component normal-basis bound and separated-weights choice. The final step uses the standard residue obstruction: an exact differential cannot equal dY/Y for a nonconstant rational function Y on an algebraic curve.
Uses
Used by
Sources
PaperOpen
- Section
- §2.2 The curve inequality
- Page
- —
- Label
—- Line
sections/interpolation.tex:327
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- infoinferred_depoutline: "Logarithmic residues force constant Y" rests on claim-geom-curve-inequality-3
- infoinferred_depoutline: "Logarithmic residues force constant Y" rests on claim-geom-interpolation-1