claimroutineinferred_dep

Outward passage bounds band mass

Outward passage gives m(s)≥c m(b)log⁡(3/s)/Dm(s)\ge c\,m(b)\log(3/s)/D for the sine-weighted mean
first 1/D1/D loss; feeds the Harnack step
Claim·§6 Propagation across a thin cylinder·inside lemPropagation across a thin cylinder

Statement (paper)

Let m(s)=∫03sin⁡(πT/3)H(T,s) dTm(s)=\int_0^3\sin(\pi T/3)H(T,s)\,dT. Then m′′+s−1m′≤(V+π2/9)mm''+s^{-1}m'\le (V+\pi^2/9)m, and m(s)≥c m(b)log⁡(3/s)/Dm(s)\ge c\,m(b)\log(3/s)/D for b≤s≤3b\le s\le 3. In particular, ∫03∫3/4≤∣τ∣≤5/4H(T,∣τ∣) dτ dT ≥ c m(b)/D\int_0^3\int_{3/4\le|\tau|\le5/4}H(T,|\tau|)\,d\tau\,dT\ \ge\ c\,m(b)/D.

In plain English

Let m(s)=∫03sin⁡(πT/3)H(T,s) dTm(s)=\int_0^3\sin(\pi T/3)H(T,s)\,dT be the sine-weighted mean of HH in TT. Then m′′+s−1m′≤(V+π2/9)mm''+s^{-1}m'\le (V+\pi^2/9)m, and m(s)≥c m(b)log⁡(3/s)/Dm(s)\ge c\,m(b)\log(3/s)/D for b≤s≤3b\le s\le 3, so the integral of H(T,∣τ∣)H(T,|\tau|) over 0≤T≤30\le T\le 3 and 3/4≤∣τ∣≤5/43/4\le|\tau|\le 5/4 is at least c m(b)/Dc\,m(b)/D.

Why it's here

Weighting by sin⁡(πT/3)\sin(\pi T/3) and integrating by parts in TT turns the subsolution inequality for EE into a radial differential inequality for mm with the extra term π2/9\pi^2/9. The comparison claim with the log-affine interpolant then gives m(s)≳m(b)log⁡(3/s)/Dm(s)\gtrsim m(b)\log(3/s)/D with no loss beyond a constant, which lets the later Harnack step pass from the inner boundary mass m(b)m(b) to HH on the unit circle at cost 1/D1/D.
Classified routine:
Obtained by a standard argument: test the subsolution inequality against the first Dirichlet eigenfunction sin(πT/3), integrate by parts in T, then apply the earlier log-affine comparison claim (claim-lem-cylinder-1) through an ODE maximum-principle comparison.

Figures

Two side-by-side rectangles in the $(T,s)$ plane, with $s=|\tau|$ drawn schematically. Panel (a), "Outward comparison", spans $0\le T\le3$ and $b\le s\le3$. A thick orange segment labelled "observed wave" lies on the bottom wall $s=b$ for $1\le T\le2$, and a shaded band $3/4\le s\le5/4$ is centred on a dashed line at $s=1$; below it is the factor at $s=1$, $\log 3/\log(3/b)$. Panel (b), "Inward comparison", spans $-1\le T\le1$ and $b\le s\le1$. Its thick teal top wall at $s=1$ is labelled "uniform lower bound", and dashed guides mark an orange dot at $(0,2b)$ labelled $H(0,2b)$; below it is the factor at $s=2b$, $\log 2/\log(1/b)$. Together the panels show the two logarithmic losses incurred in carrying the energy out to $s=1$ and back to the inner wall.
Figure 2schematicp. 22
The two comparisons, with radii s=∣τ∣s=|\tau| drawn schematically. The boundary mass on 1≤T≤21\le T\le2 bounds the mass in the shaded band from below. The mean inequality on a fixed annulus supplies a lower bound on the entire upper wall in (b). The two displayed fractions are values of the normalized radial harmonic functions. The comparison solutions with potential dominate fixed multiples of these values, giving the factor [log⁡(3/b)]−2[\log(3/b)]^{-2} at the dot. In the wave estimate, b=2Khb=2Kh: HH controls the wave norm on the marked segment and is controlled by the initial data at the dot.
What it shows
Two side-by-side rectangles in the (T,s)(T,s) plane, with s=∣τ∣s=|\tau| drawn schematically. Panel (a), "Outward comparison", spans 0≤T≤30\le T\le3 and b≤s≤3b\le s\le3. A thick orange segment labelled "observed wave" lies on the bottom wall s=bs=b for 1≤T≤21\le T\le2, and a shaded band 3/4≤s≤5/43/4\le s\le5/4 is centred on a dashed line at s=1s=1; below it is the factor at s=1s=1, log⁡3/log⁡(3/b)\log 3/\log(3/b). Panel (b), "Inward comparison", spans −1≤T≤1-1\le T\le1 and b≤s≤1b\le s\le1. Its thick teal top wall at s=1s=1 is labelled "uniform lower bound", and dashed guides mark an orange dot at (0,2b)(0,2b) labelled H(0,2b)H(0,2b); below it is the factor at s=2bs=2b, log⁡2/log⁡(1/b)\log 2/\log(1/b). Together the panels show the two logarithmic losses incurred in carrying the energy out to s=1s=1 and back to the inner wall.
Read from the image by claude-opus-5.5 · confidence 88%

Sources

PaperOpen
Section
§6 Propagation across a thin cylinder
Page
—
Label
—
Line
sections/propagation.tex:63
Leannot aligned

Phase 2 aligns this node to a Lean declaration.

Friction

  • info
    inferred_dep
    outline: "Outward passage bounds band mass" rests on claim-lem-cylinder-1