claimroutineinferred_dep
Parameter choices give final ordering gap
Parameters give if YES and if NO
closes the proof with the final gap
Statement (paper)
With the parameters chosen as above (depending only on ), for every and every one has , and the emitted instance satisfies: in the YES case , and in the NO case .
In plain English
With the parameters fixed in terms of , every and give . The emitted instance then has in the YES case and in the NO case.
Why it's here
This closes the proof of the proposition: the parameters are chosen so that the conditioned YES and NO bounds from the previous claim turn into the gap versus . Taking large makes the distinctness error smaller than . The remaining losses (, , , and the gaps between , and , ) are each a small multiple of , and the constants do not depend on or .
Classified routine:
Parameter bookkeeping that combines the conditioned YES/NO bounds of the previous claim with the distinctness bound . It chooses large and every loss a small multiple of , in the usual style of Raghavendra/Guruswami et al. ordering-CSP reductions.
Uses
Used by
Nothing in the paper
Sources
PaperOpen
- Section
- §A.2 The finite ordering transfer
- Page
- —
- Label
—- Line
appendices/finite-consequences.tex:904
Leannot aligned
Phase 2 aligns this node to a Lean declaration.
Friction
- infoinferred_depoutline: "Parameter choices give final ordering gap" rests on lem:ordering-collision
- infoinferred_depoutline: "Parameter choices give final ordering gap" rests on lem:ordering-rounding
- infoinferred_depoutline: "Parameter choices give final ordering gap" rests on claim-prop-finite-ordering-transfer-6