lemmaroutine

Kernel of block restriction map

Restriction to UAU_A vanishes only on the line A=FzA=Fz under a quadratic condition
bounds rank loss per level in the detection proof
Lemma·lem:latent-block-kernel·§3.1 The quadratic block

Statement (paper)

Let S≤B∗S\le B^* and let γ:S→X∗\gamma:S\to X^* be binary linear. For each line AA, define κA,γ:S⟶UA∗,κA,γ(z)=(γz,z)∣UA. \kappa_{A,\gamma}:S\longrightarrow U_A^*, \qquad \kappa_{A,\gamma}(z)=(\gamma_z,z)|_{U_A}. Under the trace identification, write γz(x)=Tr⁡(g(z)⋅x)\gamma_z(x)=\operatorname{Tr}(g(z)\cdot x) for the associated binary linear map g:S→F3g:S\to F^3. For every nonzero z∈Sz\in S, κA,γ(z)=0⟺A=Fzandz⋅g(z)=z1z2z3. \kappa_{A,\gamma}(z)=0 \quad\Longleftrightarrow\quad A=Fz \quad\text{and}\quad z\cdot g(z)=\sqrt{z_1z_2z_3}.

In plain English

For a binary linear map γ:S→X∗\gamma:S\to X^* with S≤B∗S\le B^*, the restriction κA,γ(z)=(γz,z)∣UA\kappa_{A,\gamma}(z)=(\gamma_z,z)|_{U_A} vanishes at a nonzero z∈Sz\in S exactly when the line is A=FzA=Fz and z⋅g(z)=z1z2z3z\cdot g(z)=\sqrt{z_1z_2z_3}, where g:S→F3g:S\to F^3 represents γ\gamma via the trace.

Why it's here

This pins down exactly when a pair (γz,z)(\gamma_z,z) dies on a block UAU_A: only on the single line A=FzA=Fz and only when a quadratic condition on g(z)g(z) holds. Using the block structure from the previous lemma (the trace annihilator of DAD_A is AA and DD vanishes on AA), it lets later arguments count or detect the kernel of the restriction to each block, which feeds the rank-drop estimates that use it.
Classified routine:
A direct computation from the block structure in lem-latent-block: since the trace annihilator of D_A is A and D vanishes on A, the kernel condition reduces to A=Fz plus a quadratic identity. This is linear-algebra bookkeeping inside the paper's own construction.

Sources

PaperOpen
Section
§3.1 The quadratic block
Page
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Label
lem:latent-block-kernel
Line
sections/02-latent.tex:176
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