claimroutineinferred_dep

Contact radical K-th power divides delta

Shows MK(s~i)KM_K(\widetilde s_i)^K divides δ\delta
large lower bound on delta from contact radicals
Claim·§2.7 The height contradiction·inside propFinite test success gives integer zero

Statement (paper)

For every slope s~i\widetilde s_i, the KKth power of the radical product satisfies MK(s~i)K∣δM_K(\widetilde s_i)^K\mid\delta, where δ\delta is the fixed integer, independent of A∈RA\in R and of the chosen representation at precision KK. This follows because vq(δ)≥Kv_q(\delta)\ge K for every prime qq counted in MK(s~i)M_K(\widetilde s_i).

In plain English

For each slope s~i\widetilde s_i, the KKth power of the contact radical product, MK(s~i)KM_K(\widetilde s_i)^K, divides the fixed integer δ\delta. Here δ\delta does not depend on A∈RA\in R or on the chosen representation at precision KK.

Why it's here

Index congruence says that at every prime qq counted in MK(s~i)M_K(\widetilde s_i), the values a~\widetilde a agree with η(a)\eta(a) modulo qKq^K. That gives vq(δ)≥Kv_q(\delta)\ge K at each such prime, and so MK(s~i)K∣δM_K(\widetilde s_i)^K\mid\delta. When δ≠0\delta\ne0 this divisibility forces ∣δ∣|\delta| to be large, which is the lower half of the height contradiction against the polynomial upper bound on δ\delta from the previous claim. The later height bound for ring elements also builds on it.
Classified routine:
Direct consequence of the index congruence proposition: agreement modulo qKq^K at each contact prime gives vq(δ)≥Kv_q(\delta)\ge K, and multiplying over the primes counted in MK(s~i)M_K(\widetilde s_i) gives the divisibility. This is simple valuation bookkeeping.

Figures

A proof-flow diagram of six boxes connected by arrows. The left column starts with varying $A\in R$ and choosing a representation at precision $K$ with slopes $\widetilde s_i$, then passes to local analysis at each prime $q\mid M_K(\widetilde s_i)$ (pole parity and coarsening), then to the paired elliptic tests giving $v_q(\widetilde a-\eta(a))\ge K$. The right column keeps the root tuple fixed with nonzero $\delta=f(\eta(\mathbf a))$ bounded by $C_fB^D$; an arrow labeled 'polynomial evaluation' and an arrow from the tests feed a box concluding $M_K(\widetilde s_i)^K\mid\delta$. A final wide box applies the five-point height estimate to get $h(\widetilde A)\ll_f B$ uniformly for $A\in R$.
Figure 1diagramp. 16
The use of one nonzero δ\delta for every A∈RA\in R. All slopes shown come from the representation chosen at the fixed ordinary precision KK, and MKM_K uses the fixed exceptional set for KK. The comparison holds for every a∈Ra\in R, so it applies to the fixed root tuple. The implied constant in the final bound is ordinary and independent of AA and a\mathbf a.
What it shows
A proof-flow diagram of six boxes connected by arrows. The left column starts with varying A∈RA\in R and choosing a representation at precision KK with slopes s~i\widetilde s_i, then passes to local analysis at each prime q∣MK(s~i)q\mid M_K(\widetilde s_i) (pole parity and coarsening), then to the paired elliptic tests giving vq(a~−η(a))≥Kv_q(\widetilde a-\eta(a))\ge K. The right column keeps the root tuple fixed with nonzero δ=f(η(a))\delta=f(\eta(\mathbf a)) bounded by CfBDC_fB^D; an arrow labeled 'polynomial evaluation' and an arrow from the tests feed a box concluding MK(s~i)K∣δM_K(\widetilde s_i)^K\mid\delta. A final wide box applies the five-point height estimate to get h(A~)≪fBh(\widetilde A)\ll_f B uniformly for A∈RA\in R.
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Sources

PaperOpen
Section
§2.7 The height contradiction
Page
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Label
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Line
sections/02-reduction.tex:792
Leannot aligned

Phase 2 aligns this node to a Lean declaration.

Friction

  • info
    inferred_dep
    outline: "Contact radical K-th power divides delta" rests on claim-red-finite-test-success-1