claimroutineinferred_dep

Conditional agreement bounded by repeated game

Given R=rR=r, agreement is at most the ∣I∣|I|-fold repeated game value
applies parallel repetition to the clean coordinates
Claim·§6.2 Vanishing advice on clean coordinates·inside lemAdvice agreement decays with clean coordinates

Statement (paper)

For every value rr of the conditioning randomness RR (with clean index set II), Pr⁡[πˉaU=aO∣R=r]≤val⁡(GE⊗∣I∣)≤(1−13600)∣I∣\Pr[\bar\pi a_U=a_O\mid R=r]\le \val(G_{\mathcal E}^{\otimes\abs{I}})\le \left(1-\frac{1}{3600}\right)^{\abs{I}}, where the right-hand side is interpreted as one when I=∅I=\varnothing.

In plain English

Conditioned on any value rr of the recorded randomness RR, with clean index set II, the probability that the strategies' outputs agree, πˉaU=aO\bar\pi a_U=a_O, is at most the value of the ∣I∣|I|-fold repetition of the game GEG_{\mathcal E}, which is at most (1−1/3600)∣I∣(1-1/3600)^{|I|} (taken as one if II is empty).

Why it's here

Given R=rR=r, the previous claim makes each side's advice input a function of rr and its own question, so the two local strategies become a strategy for the repeated game GE⊗∣I∣G_{\mathcal E}^{\otimes|I|} on the independent clean coordinates. Since OPT⁡(E)≤4/5\OPT(\mathcal E)\le 4/5 gives a constant gap, the parallel repetition theorem yields the exponential decay in ∣I∣|I|, and the next claim averages this bound over the random size of II (binomial).
Classified routine:
Follows directly from the previous claim (advice is determined by r and each side's own question) by viewing the local strategies as a strategy for the repeated game, then applying the parallel repetition bound for projection games with gap 1/5, since (1/5)^2/16 = 1/400 and 1/400 ≥ 1/3600.

Sources

PaperOpen
Section
§6.2 Vanishing advice on clean coordinates
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sections/05-clean.tex:202
Leannot aligned

Phase 2 aligns this node to a Lean declaration.

Friction

  • info
    inferred_dep
    outline: "Conditional agreement bounded by repeated game" rests on claim-lem-clean-4